Okay, there's four possibilities: 1) *The one that's a six is a six, and the other one is a six 2) *The one that's a six is a six, and the other one is not a six 3) *The one that's a six is not a six, and the other one is a six 4) *The one that's a six is not a six, and the other one is not a six.
Clearly, we can eliminate 3) and 4). That leaves us with a 1 in 6 probability that the die other than the die that's a six is also a six.
(alternate, smart-ass answer: the odds are 0, because 'one of them' means 'exactly one of them'.)
(no subject)
Date: 2011-08-18 02:01 am (UTC)1) *The one that's a six is a six, and the other one is a six
2) *The one that's a six is a six, and the other one is not a six
3) *The one that's a six is not a six, and the other one is a six
4) *The one that's a six is not a six, and the other one is not a six.
Clearly, we can eliminate 3) and 4). That leaves us with a 1 in 6 probability that the die other than the die that's a six is also a six.
(alternate, smart-ass answer: the odds are 0, because 'one of them' means 'exactly one of them'.)