theweaselking: (Science!)
[personal profile] theweaselking
Because it's Friday, and nobody loves random stupid work on a Friday more than me.

The question!:

Expand:
(x-a)(x-b)(x-c)(x-d)( ... )(x-y)(x-z)


You should be able to do this one in your sleep, if you've passed high-school algrebra.

EDIT:

(no subject)

Date: 2008-05-16 04:11 pm (UTC)
From: [identity profile] kadath.livejournal.com
Expand:
(x-a)(x-b)(x-c)(x-d)( ... )(x-y)(x-z)


No. :P

(no subject)

Date: 2008-05-16 04:15 pm (UTC)
From: [identity profile] theweaselking.livejournal.com
Oh, come on, you can't just do it in your head?

(no subject)

Date: 2008-05-16 04:17 pm (UTC)
From: [identity profile] unnamed525.livejournal.com
Yes, but I don't want to give it away.

(no subject)

Date: 2008-05-16 05:37 pm (UTC)
From: [identity profile] kadath.livejournal.com
I stopped having to do trick questions after I graduated high school and was no longer on the math team.

(no subject)

Date: 2008-05-16 04:18 pm (UTC)
From: [identity profile] publius1.livejournal.com
I COULD do this one quite easily in about four hours of painstaking work, but I'm betting there's a quick trick involved and I don't know what it is.

And considering that I definitely passed high-school algebra, you're full of it!

(no subject)

Date: 2008-05-16 04:22 pm (UTC)
From: [identity profile] theweaselking.livejournal.com
Since you passed high-school algrebra, you SHOULD be able to do this one in your sleep. If you're awake, then doing it in your head will suffice.

(no subject)

Date: 2008-05-16 04:27 pm (UTC)
From: [identity profile] publius1.livejournal.com
Oh. Duh. Yeah, I just looked it up.

Ok, see, this is not a quick trick, it's a lame-assed doesn't-count trick kind of question, where if you were a real mathematician, you'd x' it.

(no subject)

Date: 2008-05-16 04:42 pm (UTC)
From: [identity profile] elffin.livejournal.com
Google is your friend.

(no subject)

Date: 2008-05-16 04:47 pm (UTC)
From: [identity profile] dreamshade.livejournal.com
Har har, I should be able to do trick questions in my sleep. :p

The croc has a point - if you were stupid enough to think junior high algebra teaching would be a rewarding career...

I am reminded...

Date: 2008-05-16 04:53 pm (UTC)
From: [identity profile] bluetara2020.livejournal.com
x-x = 0

-coughs-

(no subject)

Date: 2008-05-16 04:55 pm (UTC)
From: [identity profile] harald387.livejournal.com
You know, I actually failed high school algebra (passing because he decided to grade on a curve is not passing), and my reason then is the same as my reason now.

Don't care, will never use this.

(no subject)

Date: 2008-05-16 05:03 pm (UTC)
From: [identity profile] a-pawson.livejournal.com
The answer is 0.

(no subject)

Date: 2008-05-16 05:09 pm (UTC)
From: [identity profile] katballou.livejournal.com
I'm just amused that if you google it the second result is this entry.

I suck hard at math

Date: 2008-05-16 05:29 pm (UTC)
From: [identity profile] marlo.livejournal.com
OOH! OOH! The answer to the comic is x=3!

(no subject)

Date: 2008-05-16 05:39 pm (UTC)
From: [identity profile] glitteringlynx.livejournal.com
For the record, I never took the actual OAC Algebra course. I only learned some of it in the first four high school grades as one section of the course. Also, I'm not great at math. The best math grade I ever got was for OAC Finite (that was a fun course!).

So.. I have no idea what the trick is to your math problem you gave.

However I *can* do this one:

3x+4=13
3x=13-4
3x=9
x=3

(no subject)

Date: 2008-05-16 05:48 pm (UTC)
From: [identity profile] theweaselking.livejournal.com
For the original quesiton: What's the third term from the end?

(no subject)

Date: 2008-05-16 05:51 pm (UTC)
From: [identity profile] glitteringlynx.livejournal.com
(x-x)

Oh, wait...

*smacks forehead*

I get it now. :)

(no subject)

Date: 2008-05-16 06:02 pm (UTC)
From: [identity profile] torrain.livejournal.com
Yeah, that was pretty much my thought process, complete with mad delay.

I did pretty well in algebra, as I recall, although calculus kicks me to the curb and back every time I even approach it. But it's been years since I've used it, and so I was rusty enough to miss that.

(no subject)

Date: 2008-05-16 06:22 pm (UTC)
From: [identity profile] glitteringlynx.livejournal.com
I graduated from high school in June 1999 (we had a fifth year in high school called OAC). I took calculus becuase I had to.. and did TERRIBLE. I was just happy I passed.

The algebra units we did in the 4 grades prior I did rather well at, once I got the hang of things. But I didn't take the actual course in algebra because.. well.. I hate math. I was far more of an English/Music person in high school.

(no subject)

Date: 2008-05-16 08:01 pm (UTC)
From: [identity profile] anivair.livejournal.com
yeah, I felt stupid, too.

(no subject)

Date: 2008-05-16 05:50 pm (UTC)
From: [identity profile] kadath.livejournal.com
So.. I have no idea what the trick is to your math problem you gave.

Any operation contained in parentheses is performed first. In the case of all the other terms, those operations cannot be done, because the values of the variables are not known. However, assuming the sequence of the expression is truly alphabetical, the third-to-last term is (x-x). By the reflexive property, x = x, and thus x - x = 0. By the zero property of multiplication (no really, that's what it's called), anything times zero is zero. Therefore, the entire expression is equal to zero, and [livejournal.com profile] theweaselking is kind of a jerk.

(no subject)

Date: 2008-05-16 05:57 pm (UTC)
From: [identity profile] publius1.livejournal.com
Well, the way I was looking at it, when he says "Expand", it does mean it can be done, but yeah, you end up with a bunch of constant letterings that just get longer and longer the more you "expand".

(x-a)(x-b) = x2 - ax - bx + ab .. lather rinse repeat. It would get rather long without the "trick" by the end, though!

(no subject)

Date: 2008-05-16 05:58 pm (UTC)
From: [identity profile] kadath.livejournal.com
The key is order of operations. Because (x-x) is in parentheses, if you don't do that operation first, you're technically not doing it right.

(no subject)

Date: 2008-05-16 06:15 pm (UTC)
From: [identity profile] publius1.livejournal.com
Well, they're ALL in parentheses, right? So if you go left to right, which is like TOTALLY legitimate and stuff, expanding the parentheses as you come to them, you're fine. (x-a)(x-b) is just one step in the looong road that you'd take until you got to (x-x) and said "well, fuck."

(no subject)

Date: 2008-05-16 06:20 pm (UTC)
From: [identity profile] kadath.livejournal.com
expanding the parentheses as you come to them

Nope, each set of parentheses takes precedence. So you go through left to right, leaving each set as you find it because it is already as simplified as possible, until you get to (x-x), which can be further simplified.

(no subject)

Date: 2008-05-16 06:59 pm (UTC)
From: [identity profile] publius1.livejournal.com
I learned Order of Operations differently from you! But you would win, because your work makes things easier.

(no subject)

Date: 2008-05-16 08:37 pm (UTC)
From: [identity profile] toddhamster.livejournal.com
But if you expand the expression algebraically, say, from left to right,
you end up with an expression equivalent to the original, only written differently. This does not violate the order of operations, it is just
an expansion.

(no subject)

Date: 2008-05-16 11:39 pm (UTC)
From: [identity profile] theweaselking.livejournal.com
And, because of the x-x term, eventually *all* of your expanded results will cancel out.

x^26 - x^26 + 25(x^25)a - 25(x^25)a + etc.

(no subject)

Date: 2008-05-16 05:46 pm (UTC)
From: [identity profile] scifantasy.livejournal.com
(Responses unseen yet...)

0.

(no subject)

Date: 2008-05-16 05:51 pm (UTC)
From: [identity profile] http://users.livejournal.com/_jeremiad/
I swear, sometimes I'm convinced I have dyscalculia.

Numbers are just not intuitive to me.

(no subject)

Date: 2008-05-16 11:42 pm (UTC)
From: [identity profile] the-colombian.livejournal.com

I go with the following equation:

Whatever math I need to count, multiply, or subtract from the money in my bank is all I'll ever need.

All other free time will be spent having sex with an attractive woman.



(no subject)

Date: 2008-05-16 05:55 pm (UTC)
From: [identity profile] atesh42.livejournal.com
Killface: And what do you think you're doing?
Simon: [mutters]
Killface: Oh, really? Well, bright young lads who bring home a C in earth science and a C minus in algebra don't get to go on a lovely kidnapping.
Simon: [mutters]
Killface: Yes, as a matter of fact, we'll probably use algebra like mad today.
(deleted comment)

(no subject)

Date: 2008-05-16 07:00 pm (UTC)
From: [identity profile] publius1.livejournal.com
Oh god! This shows up on the WoW forums all the time.

(no subject)

Date: 2008-05-16 07:06 pm (UTC)
From: [identity profile] theweaselking.livejournal.com
Without even looking at it, I said "it divides by zero".

And I was right.

(no subject)

Date: 2008-05-16 08:04 pm (UTC)
jerril: A cartoon head with caucasian skin, brown hair, and glasses. (Default)
From: [personal profile] jerril
Just to be complete here (SPOILER ALERT SPOILER ALERT):

(SPOILER ALERT SPOILER ALERT)

(SPOILER ALERT SPOILER ALERT)

(SPOILER ALERT SPOILER ALERT)

a=b
Therefore the term (a-b) is just another way of writing 0.

So between line 4, and line 5, when they eliminate the (a-b) terms on both side by dividing both sides by (a-b), they're actually dividing by zero.

-----

For those of you who may not be getting how that makes (a-b) go away (I know at least one of John's readers didn't, because I got asked about this):

pretend the left side is X*Y, not (a+b)(a-b)

you can eliminate Y by dividing by Y ...

X*Y/Y = X...

because Y/Y = 1, and anything * 1 is itself.

The whole term can be eliminated this way... except that the whole term is equal to zero, so you can't, so you get a nonsense answer.

(no subject)

Date: 2008-05-16 11:35 pm (UTC)
From: [identity profile] harald387.livejournal.com
I had to go through it five times *despite this explanation* before I finally figured it out.

I hate math, it makes me feel stupid.

(no subject)

Date: 2008-05-16 11:41 pm (UTC)
From: [identity profile] theweaselking.livejournal.com
Whenever you see a nonsensical result, look for where they've divided by zero.

(no subject)

Date: 2008-05-16 11:43 pm (UTC)
From: [identity profile] harald387.livejournal.com
That doesn't help me actually understand the problem itself, or make it any easier to find the spot where they've done so. :P

(no subject)

Date: 2008-05-17 01:12 am (UTC)
From: [identity profile] theweaselking.livejournal.com
It should. You're *not* dumb, and you've seen through harder problems.

Okay, pop quiz: someone at your workplace has a physical document, printed double-sided. They want a single PDF with all the pages, in order. However, the scanners will only scan one side of a multi-page document at a time, and nobody has a copy of Acrobat Professional or Foxit Editor to combine the scanned PDF of side 1 with the scanned PDF of side 2.

What now?

PS: Trial versions of both pieces of software ARE available, but both of them watermark the output unless you pay, and
A) nobody is willing to pay
B) a watermark is not acceptable.

Therefore, a trial version of either software is NOT a workable option.

Pop quiz. Your solution?

(no subject)

Date: 2008-05-17 01:32 am (UTC)
From: [identity profile] harald387.livejournal.com
1) Our scanners handle both sides of a multi-page document.
2) We have Acrobat Pro.
3) Lacking either, we'd BUY ONE OF THE TWO to avoid using the solution below.

That said, lacking both I'd scan each side separately, load the images into Word (or whatever, really - I like Word because it will give me nice neat pages and auto-resize the image to fit them), use PDFcreator to 'print' to a PDF, problem solved.

(no subject)

Date: 2008-05-17 01:36 am (UTC)
From: [identity profile] theweaselking.livejournal.com
Your solution involves software not in the original solution. But works, given that I did say "your workplace".

My solution was

1) Scan each side separately into a separate PDF. So I have side1.pdf and side2.pdf
2) Print one of them, single sided. Assume it's side2.pdf.
3) Interleave the original print job with the one I printed in step 2, such that I now have a full SINGLE-SIDED printout of the document.
4) Scan the full 2xpage document as a "single document", into a single PDF.

(no subject)

Date: 2008-05-17 01:54 am (UTC)
From: [identity profile] ungratefulninja.livejournal.com
Yes, sometimes people really do need a problem solved and don't have money to spend solving it. However, in the workplace, the answer "In order to do X acceptably, I need Y" is a valid answer.

Earlier post fueled by ethanol and work rage.

(no subject)

Date: 2008-05-17 01:58 am (UTC)
From: [identity profile] theweaselking.livejournal.com
When a 1200dpi scan is just 3 minutes more than a 100dpi scan, sometimes it's not worth arguing with The Money for the $60 it takes to make scanned PDF editing a possibility.

And the alternative - scan to JPG, open in Word with 1 JPG = 1 page, print to PDF using PDF Creator - is more annoying, if slightly faster.

(no subject)

Date: 2008-05-19 07:22 pm (UTC)
jerril: A cartoon head with caucasian skin, brown hair, and glasses. (Default)
From: [personal profile] jerril
The problem with this as a solution is it results in scanning a printed scan of the document, which results in quality loss, which makes my teeth curl.

Of course, apparently most office people have no problem with printing something, faxing it, scanning the fax, printing it, writing on it, and faxing it again. But they're barbarians.

(no subject)

Date: 2008-05-19 09:04 pm (UTC)
From: [identity profile] theweaselking.livejournal.com
With a good printer and a good scanner, you're not losing quality that's worth caring about on the scale of "need readable PDF image of the whole document". Not even if you then print the resultant PDF again.

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