I love this puzzle.

[theweaselking]

It's surprisingly tricky.

Comments

[frith]

Fortunately you said it was tricky or I wouldn't have counted the 'fries'. And then I forgot my grade 7 math rules. 9_9

[armiphlage]

ooooh!

[frith]

I still got it wrong since I took the images to be concrete objects and not abstract variables. Thus, it's not two orders of fries (2x[fries]) but fries squared ([fries]x[fries]). Thus, [fries] = square root of 2. Since discrete object squared is nonsense (what is cat squared? a litter? what if they're both queens?) this math problem was mean. I protest!

[theweaselking]

I don't think it's even SLIGHTLY wrong to consider "two fries" to be "fries times two" instead of "fries squared".

But I'm happy to accept the fries squared answer as being just about as good.